ERRATA
LISTING
FOR
BASIC
ENGINEERING CIRCUIT ANALYSIS, 6TH EDITION
BY
J. DAVID IRWIN
AND CHWAN-HWA JOHN WU
Key:
Blue= corrected in 1st John Wiley & Sons, Inc.
printing
Green= corrected in 2nd John Wiley & Sons, Inc. printing
Violet=corrected in 3rd John Wiley & Sons, Inc.
printing
Red= to be corrected in future printings
·
Page 18 problem
1.8. Sentence should read -----energy
delivered in one hour.
·
Page 19 problem
1.11. Problem should read 50 C passes
through the element in Fig. 1.10 from A to B.
If V1 = 90 V, determine the power required by this element
per sec., per hour, per day.
·
Page 19 problem
1.12. Remove the arrow for the current
at the bottom of the figure.
·
Page 25 Figure 2.1 Caption
Correction: (4) and (5) are high wattage fixed
resistors.
·
Mid page 42. R1 (R1 + R2
) should be R1 /(R1 + R2 )
·
Bottom of page
59. Last line of text
should read Note that I3 could also---
·
Page 89 problem
2.26. The polarity on the 12V
and 6V sources should be reversed, i.e. it should be negative up and positive
down.
·
Page 111 second
line. Change diverge to
digress.
·
Page 118 Figure E3.2. The current source is 6 mA.
·
Page 120 second
line. 24/5V should be 12/5V.
·
Page 144 Figure 3.27 part (e)
Correction: The resistor between v1 and v0
should be R2 (not R1).
·
Page 147 Figure 3.29 part (a)
Correction: The input to the non-inverting terminal of
the second op-amp from the top should be v2 (not v1).
·
Page 165 problem
3.29. The polarity on
the voltage V0 should be positive on top and negative on the bottom.
·
Page 174 problem
3.66. The polarity on the
voltage V0 should be positive on top and negative on the bottom.
·
Page 178 problem
3.78. V0 should be Vx.
·
Page 186, For the 3rd
equation, i2"(t) should be
i1"(t)
·
Page 237, Problem 4.33 The
dependent current source should be Vx/1000
·
Page 261 Third equation from the top
Correction: i(t) should be i(x) so that the
corrected equation reads as:
·
Page 266 Figure 5.10 part (b)
Correction:
The resistance in the inductor model should
be Rwinding (not Rleak).
·
Page 304 Figure 6.5 part (b)
Correction: The voltage at the open circuit terminals
should be vOC 
·
Page 314 Figure 6.8
part (e)
Correction: The voltage at the open circuit terminals
should be vOC 
·
Page 316 Line immediately following Equation 6.13
Correction: insert the word respectively after equation
6.15:
6.15
respectively.
·
Page 319 Third equation from the bottom
Correction: The equation should read: K3 = -0.020
(The
negative sign was omitted).
·
Page 339 Problem 6.36 --the unknown should be on a
down arrow on the left-most 10k Ohm resistor.
·
Page 353 Last equation on the page
Correction:
The
equation should read:
(The addition sign
between the second and third terms was omitted)
·
Page 354 second line
below Eq. 7.4. Change resonant to
natural.
·
Page 354 Third equation from the top
Correction:
The
lower case k in the third term should be capitalized (K).
·
Page 358 Second bullet item:
Correction:
The equation should read:
(the z in the second
term was omitted).
·
Page 358,
Extension Exercise E7.1. Answer should
read w0 = 0.5 rad/s.
·
Page 393, Problem 7.15.
The resistor in the circuit should be 8 Ohms.
·
Page 431 Last equation on the page
Correction: The last V of the
equation should not be bolt type.
·
Page 435 Second Equation from top of page
Correction: The 1/(1+j) multiplier should be ½.
·
Page 465, problem
8.49. Current source should have units
of Amperes.
·
Page 488 First paragraph
Correction: Remove the (ff6) place holder from the text.
·
Page 542, problem
9.43. 240-V should be 480-V.
·
Page 561, mid page, the
angle on VAN is 1.08 degrees
·
Page 566 Header Drill problem D10.5
Correction: DIRLL should be DRILL
·
Page 574, mid page, the
angle on V is 1.08 degrees
·
Page 583, first line,
Section 10.7 should read 9.7
·
Page 586, Table 10.2 Q is
in MVARS
·
Page 593, Problem 10.21, 3rd
line, 470 degrees should be 47 degrees
·
Page 604, Problem 10.81,
loads are listed backwards, load 1 is 20 kVA and Load 2 is 12kW
·
Page 623, First equation
should read V1 = V2/n
·
Page 626, In the first
equation change signs to + signs
Change V2 = + nV1
= + Ό-----
= 20.87 /_13.07 degrees V
and
I2 = + I1/n
= + 4(------
= 9.33/_-13.5degrees A
·
Page 627, E11.8 V0 is
measured top-to-bottom across the 2-Ohm resistor in the secondary
·
Page 641, Problem 11.8, the
voltage source should be a current source of 10/_0 degrees A
·
Page 650, Problem 11.41
Transfomer is ideal with a 1:2 turns ratio
·
Page 768 Fourth equation
from the top of the page
Correction: The equation should read:
(in the text the comma is omitted)
·
Page 770, Example 13.4 In
the second equation, the first exponential has a + sign
·
Page778, Table
13.2. The function inside the bracket
on right side of the 5th line should
be f(t + t0 ).
·
Page 795, problem
13.3. Statement should read If f(t) =
exp (-at)cos----- ?
·
Page 802 problem 13.52. There should be a one Ohm resistor connected
between the 1 Ohm resistor and the 2 Henry inductor.
·
Page 819, E14.1 Answer
should be 6.53 exp----
·
Page 825,
extension Exercise E14.2. Exercise should
be numbered E14.7
·
Page 965, 6.22 answer
exponent is 1.67 not 6.67
6.31 answer
is 5 mA not 5/6 mA
·
Page 965, answer to
Problem 6.43. Correct answer is 50 exp
(-50t).
·
Page 965, answer to
Problem 6.46. Minus sign missing in
front of answer for
t>0.05,
i.e. 1.97 exp-----.
·
Page 966, Answer to Problem 7.14
The answer in the back of the text should
be:
Please
note that the answer in the solutions manual is correct.
·
Page 966, answer to
Problem 7.19. Answer should be 10 exp
(-t) + 2 exp (-5t) + 8
·
Page 968, The solution to Problem 13.28 should read:
Please note that the answer in the
solutions manual is correct.
·
Page 968, answer to
Problem 13.52. Answer should be 24 t
exp (-t) u(t) V.
·
Page 971 (Index)
Page Listing for Convolution integral
Correction: Convolution integral, 787-90
(not
Convolution integral, 783-86)